Drive thru

                      Taco Bueno

                      Store# 3028

                  (940)566-2012

 

                      Ticket#176

 

3/31/2010       8:27:22 PM

1 Combo 8                   4.66

    Taco

    NO Lettuce

    NO Tomato

    MED Dr. Pepper

    Reg

1 Old Combo  1 Bueno                  6.38

    Taco

    PLUS Sour Cream                      0.35

    Beef B O B

    PLUS Sour Cream                      0.35

    LG IBC Root Beer

    Party Taco

            SubTotal        11.75

            Tax                    0.97

 

                          Total                12.71

 

                              Visa                  12.71

Acct: xxxxxxxxxx6810

Authorization: 868073

 

 

 

 

 

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Lots of odd hugs.

:P 8)

... smiley spam.

*hugs Anox*

I love hugs.

I used to never like being touched :)

Used to..?

What's changed?

Used to, I met someone a long time ago and she showed me it isn't so bad.

Wow, how much is a long time since you've lived for a thousand and one years? :D

You're supposed to round that down to 28. It's simple math.

Well, considering I take A level maths, I could definitely tell that you would round 1001 to 1000 and not to 28! ;) The Maths King will not be made a fool of! :D

Prove your math. Differentiate

x^2 * arcsin x 

Um... it says 10,001 not 1001 :p

x^2*arcsinx differentiates into 2x*arcsin

I know x^2 differentiates into 2x, but I've never come across differentiating arcsinx,yet, so I took a guess. :D

I'll give you a question: Find the sum to infinity of the following series

5+2.5+1.25+0.625+...

Feel free to ask me another question.

And sorry Anox. I meant to write 10001 not 1001.

That answer is wrong :)

Oh yeah, I forgot you have to multiply the two terms together before differentiating. I'll hold my hands up and say that I've never come across arcsin, so this is my best attempt.:

x^2*arcsinx = arcsinx^3; which differentiates into = 3arcsinx^2

Is this correct? If not then tell me how to do it, so then I learn something new! :D 

That kind of math is so simple I won't even lower myself trying to explain it to you........

riiiight, that's what you say! ;)

Bloody hell... You haven't had calc yet? :P

Bloody hell... You haven't had calc yet? :P

 

Who? Me? Ummm...I've had High School algebra 1. That's it in math. That other dude is almost certainly, much better at math than I am.

hahahahahahahahahahahahahahahaahahahaha ;D

That was a question to you David :P

Yeah, I know! :D

And no I've never done calculus. Though, I don't see the harm in you teaching me something.

So, does the 10001 years old Vampire Pharoah have the patience to teach me?

And btw Kovam, I'm pretty good in maths, and the best in my year, if I do say so myself! ;)

The squaring function ƒ(x) = x² is differentiable at x = 3, and its derivative there is 6. This result is established by writing the difference quotient as follows:

 

 

 

Ex:  {f(3+h)-f(3)\ h} = {(3+h)^2 - 9\over{h}} = {9 + 6h + h^2 - 9\{h}} = {6h + h^2\{h}} = 6 + h.

 

Oh yes, I'm not a Pharaoh :)

I'm impressed but there's a couple of things I don't agree with. Please correct me if I'm wrong.

This is what you wrote:

{f(3+h)-f(3)\ h} = {(3+h)^2 - 9\over{h}} = {9 + 6h + h^2 - 9\{h}} = {6h + h^2\{h}} = 6 + h.

Doesn't: 6h + h^2\{h} = 6h + h; which factorises into = h(6+1) = 7h 

 

Also: From {[glow=red,2,300]9[/glow] + 6h + h^2 - 9\{h}}  to {6h + h^2\{h}}, I want to know where the 9 disappears to.