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There are two 9s but one is by itself, and is the number 9 and the other is part of a fraction, and would not equal to 9, so I disagree with you the two numbers { 9 - 9\h} would not cancel out.

Can you please write out for me the two terms that will cancel out, as I'm not entirely sure.

Then I'll know where I stand.

Btw are you a maths teacher or something or do you still remember all your maths from you were younger?

Or are vampires generally good at maths?! :D

Vampires are generally good at everything, although I do better with languages.

 

The last expression shows that the difference quotient equals 6 + h when h is not zero and is undefined when h is zero. (Remember that because of the definition of the difference quotient, the difference quotient is never defined when h is zero.) However, there is a natural way of filling in a value for the difference quotient at zero, namely 6. Hence the slope of the graph of the squaring function at the point (3, 9) is 6, and so its derivative at x = 3 is ƒ '(3) = 6.

Ok, I honestly haven't understood some of what you've just said; but you seem to know what you're talking about, so I'll concede on this one. *bows to the Vampire Maths Emperess*

This is fun! Give me another question! :D

Hoo, yeah "I'm on a Boat" by Lonely Island is daaaaa best. i really wanna quote but pg13 tells me otherwise but still i think it is a pg13 song anyway. have you heard 13 year olds these days??

Also, "like a boss" both my favourites.

have you also heard?: ahhmm :-[

-**** in a box

-who said we're wack

-**** in my pants

 

lonely island is coolio

First what is arcsin?

 

Do you know the trig ratio sine? Well when graphing it, the equation looks like this: [y = sin x]. But create the inverse of this and you get: [x = sin y]. But this is difficult to work with so we re-arrange again to get [y = arcsin x]. You see [x = sin y] = [y = arcsin x].

 

It's differentiable is:

          1            __

(SQRT[1 - x^2] )

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